De Broglie wavelength is given by lambda equals h over p.

the verdict

SUPPORTED

the evidence backs this

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1 source for · 0 against

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AS REPORTEDno primary record reached; this is what the reporting says

Is it true that de Broglie wavelength is given by lambda equals h over p?

Yes. The formula stating that the de Broglie wavelength equals Planck's constant divided by momentum is a standard physics definition, supported by background on de Broglie waves.

Verdict: SUPPORTED · 1 source for, 0 against · Last checked 4 Aug 2026

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Evidence for · 1

Wikipedia: Matter wave

Reference article covering this claim directly

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Wikipedia: Matter wave. (n.d.). Wikipedia. https://en.wikipedia.org/wiki/Matter_wave

Related receipts

Is it true that wavelength is represented in equations by the Greek letter lambda? SUPPORTED related question, same topic
Is it true that frequency equals wave speed divided by wavelength? SUPPORTED related question, same topic

Receipt History

first checked04 Aug 2026

judged → SUPPORTED · 7504 Aug 2026

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