The exit area of the SSME nozzle can be derived from sea level and vacuum thrust values
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A technical forum discussion demonstrates that the exit plane area of the Space Shuttle Main Engine (SSME) nozzle can be derived using the standard rocket thrust equation combined with the known sea level and vacuum thrust values alongside ambient pressure.
# What is the area of the SSME nozzle knowing only thrust at sea level and in vacuum?
Tags: engines, engine-design, nozzle, ssme
- Score: 9
- Views: 823
- Answers: 1
- Answered: yes
- Asked by: Julio Gonzalez-Saenz (91 rep)
- Asked: 2022-09-25
- Edited: 2022-09-25
- Site: space
## Question
Looking at the SSME Wikipedia RS-25 Space Shuttle Engines, the data shown that the thrust at sea level ($F_{sl}$) is 1.816*10$^6$ N, while the thrust in vacuum ($F_{vac}$) is 2.278*10$^6$ N. Knowing only these two pieces of information, I need to find out the exit plane area of the Nozzle.
I understand $\dot{m}_{sl} = \dot{m}_{vac}$, but I cannot find the correct relationship to include the formula of Thrust $F_{*} = \rho*A_e*v^2_{e}$.
I found this question in the book I am currently studying. It is problem 1.2 of "Astronautics. The Physics of Space Flight", Second Edition, Ulrich Walter.
## Answers
### Answer by Organic Marble (score: 12)
You can use the method I explained at the start of this answer: Falcon 9 Merlin 1d thrust calculated through every moment of flight
Quoting from that, you use the thrust equation:
$ \ \ \ F = \dot{m}_\mathrm e V_\mathrm e + (p_\mathrm e - p_0) A_\mathrm