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the claim
A totally ordered set with a last element but no first element is logically possible
the verdict
CONTESTED
contested - the weight sits with the supporting side
refutedsupported
the weight of evidence
2 sources for · 0 against

The available mathematical sources discuss properties of totally ordered sets such as having a first element without a last element, but do not provide explicit support for the existence of a totally ordered set with a last element and no first element.

Evidence for · 2
cited by 0
The author proves the classical theorems stating that each totally ordered set has a completion and that a complete, separable, order-dense set without a first or last element is order-isomorphic to the reals.
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The analysis

rails:sufficiency:supported:for=2+0p:against=0+0p | v55:sufficiency | v55:coherence_repaired:what=both

More for · 1
cited by 0
integers, a totally ordered set with a first element (0) but no last element, based on … X o( a lin- early ordered set A there is a first element and a last element. 168 CHARACTERIZATION … equal to) of arithmetic, with no first element but a last element. (9c) is a total order
Everything we examined (2)
This check searched the claim as stated. It did not run a separate search for evidence against it.
  1. The completion of an ordered setpeer-reviewedno side taken
  2. The vastness of natural languagesreferenceno side taken
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